A can do a piece of work in 40 days and is 100% more efficient than B. B and C complete 10% of the work in 1 day. In how many days can C alone complete the work?

80/7
97/7
24/7
33/7

Correct answer: 80/7

Solution

A completes the work in 40 days, so A’s rate is 1/40 per day. Since A is 100% more efficient than B, B’s rate is half of A’s, i.e. 1/80 per day. Given B and C together do 10% of the work in 1 day, their combined rate is 1/10, so C’s rate is 1/10 - 1/80 = 7/80, hence C alone takes 80/7 days.

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