In each of these questions, two equations (I) and (II) are given. Solve both equations and give the answer. I. $x^2 + x - 12 = 0$ II. $y^2 + 2y - 15 = 0$

x ≥ y
x = y or no relation
x > y
x < y

Correct answer: x = y or no relation

Solution

The first equation gives $x=3$ or $x=-4$. The second gives $y=3$ or $y=-5$. Since one possible pair is $x=3, y=3$ and another is $x=-4, y=-5$, while other combinations give different relations, the only safe conclusion is 'x = y or no relation'.

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