I. $6x^2 - 7x + 2 = 0$ II. $2y^2 - 5y + 3 = 0$ A) $x > y$ B) $x < y$ C) $x \ge y$ D) $x \le y$

x > y
x < y
x ≥ y
x ≤ y

Correct answer: x < y

Solution

The first equation factors as $(3x-2)(2x-1)=0$, giving roots $x=\frac{2}{3}, \frac{1}{2}$. The second factors as $(2y-3)(y-1)=0$, giving roots $y=\frac{3}{2}, 1$. In all cases, the roots of $x$ are less than the roots of $y$, so $x<y$.

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