I. x^2 - 8x + 16 = 0 II. y^2 - 7y + 12 = 0 Solve and mark the appropriate answer.

x > y
x < y
x ≥ y
x ≤ y

Correct answer: x ≥ y

Solution

The first equation factors as (x - 4)^2 = 0, so x = 4. The second equation factors as (y - 3)(y - 4) = 0, so y = 3 or 4. Hence x is always greater than or equal to y.

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