I. $x^2 + 9x + 20 = 0$ II. $8y^2 - 15y + 7 = 0$ Compare the values of $x$ and $y$.

x > y
x < y
x ≥ y
x ≤ y

Correct answer: x < y

Solution

Factor the equations to get the roots. For $x^2+9x+20=0$, roots are $x=-4,-5$; for $8y^2-15y+7=0$, roots are $y=1,\frac{7}{8}$. Comparing the intended values in such questions gives $x<y$.

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