I. $x^2 - 2.5x - 44 = 0$ II. $y^2 - 0.5y - 52.5 = 0$ Find the relation between $x$ and $y$.

x > y
x < y
x ≥ y
If x = y or relation between x and y cannot be determined.

Correct answer: If x = y or relation between x and y cannot be determined.

Solution

Solving the quadratics gives two possible values for each variable. Since one pair can make $x=y$ and another pair can make $x<y$ or $x>y$, a definite relation cannot be established. Hence the correct conclusion is that the relation cannot be determined.

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