In the following question, two equations are given. You have to solve the question and mark the answer accordingly. I. $5x^2 + 8x + 3 = 0$ II. $6y^2 + 7y - 3 = 0$

x > y
x = y or relation between cannot be established
x ≥ y
x ≤ y

Correct answer: x = y or relation between cannot be established

Solution

The roots of $5x^2+8x+3=0$ are $x=-1$ and $x=-\frac{3}{5}$, while the roots of $6y^2+7y-3=0$ are $y=\frac{1}{3}$ and $y=-\frac{3}{2}$. Since some choices of $x$ are greater than $y$ and some are not, a definite relation cannot be established. Therefore, the correct option is the one stating that the relation cannot be established.

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