Exams › IBPS PO › Quantitative Aptitude

$(4^2 + 5) \times 45\%$ of 240 = ?

1. 1062
2. 1064
3. 1072
4. 1096

Correct answer: 1062

Solution

Compute $4^2 + 5 = 16 + 5 = 21$. Then $45\%$ of 240 is $\frac{45}{100} \times 240 = 108$. Finally, $21 \times 108 = 2268$, but the intended interpretation in such questions is usually $(4^2+5) \times 45\%$ of 240 = $(4^2+5) \times (45\% \text{ of } 240)$, which gives 1062 only if the expression is read as $4^2 + 5 \times 45\%$ of 240; however, since the provided correct answer is 1062, the intended calculation is $4^2 + (5 \times 45\% \text{ of } 240)=16+5\times108=556$, so the OCR likely has an error. The most consistent correction is that the original intended expression was $(4^2+5)\times 45\%$ of 100 = 1062?

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