I. $3x^2 + 7x + 4 = 0$ II. $y^2 + 9y + 20 = 0$ Choose the correct relation between $x$ and $y$.

if x > y
if x ≥ y
if y > x
if y ≥ x

Correct answer: if x > y

Solution

The first equation factors as $(3x+4)(x+1)=0$, so $x=-\frac{4}{3}$ or $x=-1$. The second factors as $(y+4)(y+5)=0$, so $y=-4$ or $y=-5$. In every possible case, $x>y$.

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