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Car X travels for 4 hours to reach from point A to B. Car Y travels at a speed of 70 km/h to reach from point B to C in 3 hours. The distance travelled by car X to cover A to B is \(\tfrac{1}{7}\) more than the distance travelled by car Y. How much time will car X take to reach from point A to C?

1. 9 hours
2. 7.5 hours
3. 5 hours
4. 12 hours

Correct answer: 7.5 hours

Solution

Car Y covers \(70 \times 3 = 210\) km. Car X covers \(\tfrac{1}{7}\) more than this, so distance AB = \(210 \times \tfrac{8}{7} = 240\) km. Since car X takes 4 hours for AB, its speed is 60 km/h; total distance AC = 240 + 210 = 450 km, so time = 450/60 = 7.5 hours.

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