Exams › IBPS PO › Quantitative Aptitude
Correct answer: 6 m
From the 100 m race, when A runs 100 m, B runs 90 m and C runs 87 m. So \(B:C=90:87=30:29\). Therefore, when B runs 180 m, C runs \(180\times \frac{29}{30}=174\) m, so B beats C by 6 m.
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