Exams › IBPS PO › Quantitative Aptitude

The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:

1. Rs. 3500
2. Rs. 3750
3. Rs. 3840
4. Rs. 3900

Correct answer: Rs. 3900

Solution

Let chair price be \(c\) and table price be \(t\). From \(10c=4t\), we get \(5c=2t\) or \(t=2.5c\). Using \(15c+2t=4000\), we get \(15c+5c=20c=4000\Rightarrow c=200\), so \(t=500\). Then \(12c+3t=2400+1500=3900\).

Related IBPS PO Quantitative Aptitude questions

• There are two examination rooms, A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number in B. The number of students in room A is:
• Solve the system of equations: $4x + 7y = 42$ and $3x - 11y = -1$. Find $x$ and $y$.
• I. $x^2 - 16x + 64 = 0 \rightarrow x = 8, 8$ II. $y^2 - 16y + 63 = 0 \rightarrow y = 9, 7$ So, $x \le y$.
• In the following question, two equations are given in variables x and y. On the basis of these equations, decide the relation between x and y. I. 3x + 2y = 301 II. 7x - 5y = 74
• In the following question, two equations (I) and (II) are given. Solve both equations and answer the question. I. $3x + 2y = 7$ II. $2x + 5y = 12$
• I) $x = 3y - 24$ II) $15y + 2y^2 = 37y$

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →