Exams › IBPS PO › Quantitative Aptitude

What least number must be added to 1056 so that the sum is completely divisible by 23?

1. 2
2. 3
3. 18
4. 21

Correct answer: 2

Solution

Dividing 1056 by 23 gives a remainder of 21, since \(23 \times 45 = 1035\) and \(1056-1035=21\). To reach the next multiple of 23, add \(23-21=2\).

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