StreakPeaked· Practice

ExamsIBPS POGeneral Awareness

A man invested ₹X in compound interest at 20% p.a. for two years, and he invested the same amount in simple interest for three years at 21% p.a. If the difference between the interests is ₹1900, then find X.

  1. 10000
  2. 12000
  3. 14000
  4. 8000

Correct answer: 10000

Solution

Compound interest for 2 years at 20% is \(X[(1.2)^2-1]=0.44X\). Simple interest for 3 years at 21% is \(X\times 21\times 3/100=0.63X\). Their difference is \(0.63X-0.44X=0.19X=1900\), so \(X=10000\).

Related IBPS PO General Awareness questions

⚔️ Practice IBPS PO General Awareness free + battle 1v1 →