The given caselet gives the information about the number of managers (male + female) and the number of clerks (male + female) working in three different companies X, Y and Z. - Total managers in X = 90 - Female clerks in X are 10 less than total managers in X $\rightarrow 80$ - Male cler

Question

The given caselet gives the information about the number of managers (male + female) and the number of clerks (male + female) working in three different companies X, Y and Z. - Total managers in X = 90 - Female clerks in X are 10 less than total managers in X $\rightarrow 80$ - Male clerks : female clerks in X = 9:8 $\rightarrow$ male clerks = 90 - Male managers in Z are 10 more than female managers in Z - Total managers in Z = female clerks in X = 80 - Male clerks in Z are 10 more than in X $\rightarrow 100$ - Total clerks in Z = 165 $\rightarrow$ female clerks in Z = 65 - Average of male and female managers in Z = female clerks in Y = 30 less than males in Y - Male : female managers in Y = 4:5 - Difference between male and female managers in Y = 15 - Male : female managers in X = 5:4 If the number of male managers and female managers in company Z is increased by 20% and 40% respectively, find the difference between the total male managers in all the given companies and the total female managers in all the given companies.

Accepted Answer

0. From the data, company Z has 80 managers with male and female managers differing by 10, so they are 45 and 35. Company Y has managers in the ratio 4:5 with difference 15, so male and female managers are 60 and 75. Company X has managers in the ratio 5:4 with total 90, so male and female managers are 50 and 40. After increasing Z's male managers by 20% and female managers by 40%, they become 54 and 49, and the totals of male and female managers across all companies both become 164, so the difference is 0.

Solution

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