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The number of d-electrons in Fe$^{2+}$ (Z = 26) is not equal to that of

1. p-electrons in Ne (Z = 10)
2. s-electrons in Mg (Z = 12)
3. d-electrons in Fe (Z = 26)
4. p-electrons in Cl (Z = 17)

Correct answer: p-electrons in Cl (Z = 17)

Solution

Fe has electronic configuration [Ar] 3d$^6$ 4s$^2$, so Fe$^{2+}$ becomes [Ar] 3d$^6$. Chlorine has configuration 1s$^2$ 2s$^2$ 2p$^6$ 3s$^2$ 3p$^5$, so it has 5 p-electrons, which is not equal to 6. The other options match 6 d-electrons.

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