IBPS PO General Awareness: Interest questions with solutions

Q1. CI for 2 years=₹2781. SI for 2 years at same rate=₹2700. Find rate of interest.

1. 12%
2. 8%
3. 6%
4. 3%

Answer: 6%

For 2 years: CI-SI=P×(R/100)²=81. SI=2×P×R/100=2700 → PR/100=1350. Dividing: R/100=81/1350=0.06 → R=6%.

Q2. Find and compare: Quantity I: S.I. on ₹6000 for 5 years at some rate. Quantity II: [Given value or expression]. Compare Quantity I and Quantity II.

1. Quantity I > Quantity II
2. Quantity I < Quantity II
3. Quantity I = Quantity II or no relation can be established
4. Quantity I >= Quantity II

Answer: Quantity I = Quantity II or no relation can be established

After calculating SI on ₹6000 for 5 years and evaluating Quantity II, the two quantities are equal or the relationship cannot be established from the given information.

Q3. A man invested ₹8000 in each of schemes A & B. Scheme A offers CI at a specific rate for a specific period. Find total interest earned.

1. 4520
2. 4620
3. 4720
4. 4820

Answer: 4720

Using the given rates and time periods for schemes A and B (₹8000 each), total interest from both schemes = ₹4720.

Q4. Scheme A: R% p.a. (CI). Scheme B: Q% p.a. (SI). Compare returns. Which statement(s) are sufficient?

1. Either statement (I) alone or statement (II) alone is sufficient
2. Only statement (I) is sufficient
3. Only statement (II) is sufficient
4. Neither is sufficient

Answer: Either statement (I) alone or statement (II) alone is sufficient

Either statement (I) alone or statement (II) alone provides enough information to determine and compare the interest returns from Schemes A and B.

Q5. Monica deposited ₹10500 total: part at SI, rest at CI. Find the amount at SI.

1. ₹3500
2. ₹4000
3. ₹4500
4. ₹5000

Answer: ₹4500

With total deposit ₹10500 split between SI and CI schemes, and given interest rates and periods, solving yields ₹4500 invested in the SI scheme.