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A rectangular hole of size 100 mm × 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 MPa and 300 MPa, respectively. The hole is made by punching process. Neglecting the effect of clearance, the punching force (in kN) is

1. 300
2. 450
3. 600
4. 750

Correct answer: 450

Solution

Punching force = sheared perimeter * thickness * shear strength. Perimeter = 2(100+50)=300 mm. F = 300 mm * 5 mm * 300 MPa = 450000 N = 450 kN.

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