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Statement for Linked Answer Questions 52 and 53: In orthogonal turning of a bar of 100 mm diameter with a feed of 0.25 mm/rev, depth of cut of 4 mm and cutting velocity of 90 m/min, it is observed that the main (tangential) cutting force is perpendicular to the friction force acting at the chip-tool interface. The main (tangential) cutting force is 1500 N. Q.52 The orthogonal rake angle of the cutting tool in degree is
- zero
- 3.58
- 5
- 7.16
Correct answer: zero
Solution
The orthogonal rake angle is zero because the main cutting force is perpendicular to the friction force, indicating that the cutting action is purely orthogonal with no inclination of the cutting edge.
Related GATE Technical questions
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- Statement for Linked Answer Questions 54 and 55:
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- Statement for Linked Answer Questions 57 and 58:
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