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In a cam-follower, the follower rises by h as the cam rotates by δ (radians) at constant angular velocity ω (radians/s). The follower is uniformly accelerating during the first half of the rise period and is uniformly decelerating in the latter half of the rise period. Assuming that the magnitudes of the acceleration and deceleration are same, the maximum velocity of the follower is

1. 4hω/δ
2. hω
3. 2hω/δ
4. 2hω

Correct answer: 2hω/δ

Solution

The maximum velocity of the follower occurs at the midpoint of its rise, where it has accelerated uniformly to its peak speed. Given the uniform acceleration and deceleration, the relationship between the rise height, angular displacement, and angular velocity leads to the formula for maximum velocity being 2hω/δ.

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