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A block of mass 10 kg rests on a horizontal floor. The acceleration due to gravity is 9.81 m/s². The coefficient of static friction between the floor and the block is 0.2. A horizontal force of 10 N is applied on the block as shown in the figure. The magnitude of force of friction (in N) on the block is ____
- 2
- 10
- 19.62
- 0
Correct answer: 10
Solution
Maximum static friction = mu*N = 0.2*10*9.81 = 19.62 N. The applied 10 N is less than this, so the block stays at rest and friction exactly balances the applied force at 10 N.
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