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The ac bridge shown in the figure is used to measure the impedance Z. If the bridge is balanced for oscillator frequency f = 2 kHz, then the impedance Z will be
- (260 + j0) a9
- (0 + j200) a9
- (260 - j200) a9
- (260 + j200) a9
Correct answer: (260 + j200) a9
Solution
In an AC bridge, balance conditions relate the product of opposite arms. Using the given balance at 2 kHz, the unknown impedance resolves to a positive resistance and positive reactance. Hence Z = (260 + j200) a9.
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