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A voltage 1000 sin πt V volts is applied across Y Z. Assuming ideal diodes, the voltage measured across W X in volts is.

1. sin πt
2. (sin πt + |sin πt|)/2
3. (sin πt - |sin πt|)/2
4. 0 for all t

Correct answer: (sin πt + |sin πt|)/2

Solution

The correct option represents the output voltage across W X when an AC voltage is applied and ideal diodes are used. The expression (sin πt + |sin πt|)/2 effectively captures the positive half-cycles of the sine wave, allowing current to pass through the diodes, while blocking the negative half-cycles, resulting in a rectified output.

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