Correct answer: Only I, III and IV
Options I, III, and IV are equivalent because they all yield the same result by focusing on the common key attributes P and Q from both relations R and S. Option I directly joins R and S and projects P, while III uses intersection to find common keys, and IV effectively retrieves the same keys by eliminating non-matching entries. Option II, however, does not guarantee the same result as it joins the projections of R and S separately, which may lead to different outcomes.