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The minimum number of comparisons required to determine if an integer appears more than n/2 times in a sorted array of n integers is

1. Θ(n)
2. Θ(log n)
3. Θ(log* n)
4. Θ(1)

Correct answer: Θ(log n)

Solution

In a sorted array, we can efficiently find the target integer using binary search, which reduces the search space by half with each comparison, resulting in a time complexity of Θ(log n) to determine if the integer appears more than n/2 times.

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