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The chainage of the intersection point of two straights is 585.60 m and the angle of intersection is 140°. If the radius of a circular curve is 600.00 m, the tangent distance and length of the curve, respectively, are

1. 418.88 and 1466.08
2. 218.38 and 1648.49
3. 218.38 and 418.88
4. 418.88 and 218.38

Correct answer: 218.38 and 418.88

Solution

The intersection angle is 140°, so the deflection angle is \(\Delta = 180°-140° = 40°\). Then \(T = 600\tan 20° \approx 218.38\) m and \(L = \pi\times 600\times 40/180 \approx 418.88\) m. Therefore the correct pair is 218.38 and 418.88.

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