Exams › GATE › Technical › Electronics and Communication Engineering (Set 3)
10 questions with worked solutions.
Answer: 20
In steady state, the ideal diodes D1 and D2 conduct during the positive and negative halves of the AC cycle, respectively, allowing the full amplitude of the AC voltage to appear across the load resistor R. Since the AC source has a peak voltage of 10 volts, the output voltage V0 across R effectively doubles to 20 volts due to the contributions from both halves of the waveform.
Answer: 4F and 1
A7 = 1010 0111. RLC rotates left: the MSB (1) goes to carry and to the LSB, giving 0100 1111 = 4F with carry = 1. Correct option is 3 (4F and 1), not stored option 1 (4E and 1).
Q3. The minimum number of 2-input NAND gates required to implement a 2-input XOR gate is
Answer: 4
A 2-input XOR gate can be constructed using 4 2-input NAND gates by combining them in a specific configuration that utilizes the properties of NAND gates to achieve the desired output of the XOR function.
Answer: G = G1G2 / (1 + G1G2 + G1G2H1)
The correct option accounts for the contributions of both the forward path gains and the feedback loop, accurately representing the overall closed-loop gain by including all relevant terms in the denominator.
Answer: 0
The steady state error for a unity feedback system with a type 1 system (one integrator in the open-loop transfer function) is zero for a unit step input, as the system can perfectly track the input due to its ability to eliminate steady state error.
Answer: (C) A triangular waveform from t = 0 to 2Tₛ with peak value 1 at t = Tₛ
The correct option describes the output of the matched filter for a rectangular pulse input, which results in a triangular waveform due to the convolution of the pulse shape with itself. The peak occurs at the midpoint of the pulse duration, specifically at Tₛ, and the waveform extends from 0 to 2Tₛ, reflecting the integration of the signal over time.
Answer: (B) left-handed circularly polarized
When a right-handed circularly polarized wave reflects off a perfect conductor, the phase of the electric field component reverses, resulting in a left-handed circularly polarized wave.
Answer: (C) ∇ × E = −∂B/∂t
Option (C) correctly represents Faraday's law of electromagnetic induction, which states that a changing magnetic field over time induces an electric field. This relationship is fundamental in electromagnetism and is mathematically expressed through the curl of the electric field being equal to the negative rate of change of the magnetic field.
Answer: controllable but not observable
With x1' = -2x1 + 3u, x2' = -x2 + u, the controllability matrix has full rank 2 (both states driven by u), but with c = x1 the observability matrix has rank 1 (x2 is hidden). So the system is controllable but not observable, option 0, not stored option 1.
Answer: 2R_X(τ) + R_X(τ - T₀) + R_X(τ + T₀)
The correct option reflects the properties of the autocorrelation function when a wide sense stationary process passes through a linear time-invariant (LTI) system, where the output's autocorrelation is influenced by the input's autocorrelation at different time shifts, specifically incorporating contributions from both positive and negative shifts of T₀.