Exams › SSC CGL (Prelims) › Maths › Time and Work
2 questions with worked solutions.
Answer: 14⅔
Pipe A fills in 20 h and B in 30 h, so together they fill at $\frac{1}{20}+\frac{1}{30}=\frac{1}{12}$ tank per hour. One-third of the tank is filled in 4 hours; after that, only $\frac{3}{4}$ of the combined supply is effective, so the net rate becomes $\frac{3}{4}\times\frac{1}{12}=\frac{1}{16}$ tank per hour. The remaining two-thirds takes $\frac{2/3}{1/16}=10\frac{2}{3}$ hours, giving total time $4+10\frac{2}{3}=14\frac{2}{3}$ hours.
Answer: 16
Total work = 8 × 12 = 96 worker-days. If 6 workers do the same work, days required = 96 ÷ 6 = 16.