Exams › SSC CGL (Prelims) › Maths

In triangle LMN, \(\angle L = 118^\circ\) and \(LM = LN\). Find \(\angle N\).

1. 42°
2. 31°
3. 65°
4. 62°

Correct answer: 31°

Solution

Since \(LM = LN\), triangle LMN is isosceles with base \(MN\), so \(\angle M = \angle N\). The remaining angles sum to \(180^\circ - 118^\circ = 62^\circ\), so each base angle is \(62^\circ/2 = 31^\circ\).

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