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ExamsSSC CGL (Prelims)Maths

The number 4,29,714 is divisible by:

  1. 3 and 5
  2. 6 and 5
  3. 4 and 6
  4. 3 and 6

Correct answer: 3 and 6

Solution

For divisibility by 3, the sum of digits is 4+2+9+7+1+4=27, which is divisible by 3. For divisibility by 6, the number must be divisible by 2 and 3; it is even and already divisible by 3, so it is divisible by 6.

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