Exams › SSC CGL (Prelims) › Maths
Correct answer: 3 and 6
For divisibility by 3, the sum of digits is 4+2+9+7+1+4=27, which is divisible by 3. For divisibility by 6, the number must be divisible by 2 and 3; it is even and already divisible by 3, so it is divisible by 6.