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ExamsSSC CGL (Prelims)Maths

In $\triangle PQR$, if $4\angle P = 5\angle Q = 20\angle R$, then the value of $\angle Q$ is:

  1. 72°
  2. 36°
  3. 90°
  4. 45°

Correct answer: 72°

Solution

Let $4P=5Q=20R=k$. Then $P=\frac{k}{4}$, $Q=\frac{k}{5}$, and $R=\frac{k}{20}$. Using $P+Q+R=180^\circ$, we get $\frac{k}{4}+\frac{k}{5}+\frac{k}{20}=180$, so $k=360$ and hence $Q=\frac{360}{5}=72^\circ$.

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