Exams › SSC CGL (Prelims) › General › Simplification
1 questions with worked solutions.
Q1. If ‘P’ means addition, ‘D’ means subtraction, ‘S’ means multiplication, and ‘V’ means division, find the value of \{24P(18D6)\}V(6S2)P12V(6).
Answer: 5
Replace the symbols: \{24 + (18 - 6)\} ÷ (6 × 2) + 12 ÷ 6. This becomes \{24 + 12\} ÷ 12 + 2 = 36 ÷ 12 + 2 = 3 + 2 = 5.
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