Exams › SSC CGL (Prelims) › General › Simple and Compound Interest
16 questions with worked solutions.
Answer: ₹ 10,625
With annual compounding for 1.5 years, amount after 1 year is \(1.2P\). For the next half-year, simple interest at 20% p.a. on \(1.2P\) is \(0.1\times1.2P=0.12P\). Total CI is \(0.2P+0.12P=0.32P=3400\), giving \(P=10625\).
Answer: ₹ 1,456
For 3 years, compound interest is $P\left[(1+r)^3-1\right]$, where $r=14\tfrac{2}{3}\%=\frac{11}{75}$. Using the given CI, we get the principal, and then simple interest for 3 years at the same rate comes out to ₹1,456.
Q3. In how many years will Rs. 80,000 become Rs. 1,06,480 at 10% compound interest per annum?
Answer: 3
Under compound interest, amount after n years is \(80000(1.1)^n\). Now \(80000\times1.1^3 = 80000\times1.331 = 106480\). Therefore, the required time is 3 years.
Q4. Find the compound interest on ₹9,500 at 11% p.a. for 2 years 6 months, compounded annually.
Answer: ₹ 2,848.72
For annual compounding, compute the amount after 2 years and then apply simple interest for the remaining 6 months on that amount. The difference between the final amount and principal gives the compound interest.
Answer: 10%
In compound interest, successive yearly amounts differ by a constant factor of (1+r). The ratio 26400/24000 = 1.1, so the rate is 10% per annum.
Answer: 2,997
At 16% per annum compounded quarterly, the rate per quarter is 4%. For 9 months, there are 3 quarters. Amount = \(24000(1.04)^3\approx 26997\), so compound interest = \(26997-24000=2997\).
Answer: 50%
If the money becomes 2.25 times in 2 years, then \((1+r)^2 = 2.25\). So \(1+r = 1.5\), giving \(r = 0.5 = 50\%\).
Answer: 6,945.75
For annual compounding, amount after 3 years is \(6000(1.05)^3\). This equals \(6000 \times 1.157625 = 6945.75\). Hence the amount is Rs. 6,945.75.
Answer: 45
If the money doubles in 15 years, then each 15-year period multiplies it by 2. To become eight times, it must double three times because \(8=2^3\). Therefore, the required time is \(3\times15=45\) years.
Answer: 10%
The amount increases from 8800 to 9680 in one year, so the yearly growth factor is $9680/8800 = 1.1$. This means the rate is 10% per annum.
Q11. Calculate the compound interest on Rs. 5000 for 2 years at 20% per annum, compounded half-yearly.
Answer: 2,320.50
At 20% p.a. compounded half-yearly, the rate per half-year is 10% and the number of periods in 2 years is 4. Amount = 5000(1.1)^4 = 7320.50, so compound interest = 7320.50 - 5000 = 2320.50.
Answer: 18
If the amount triples in 6 years, then in each 6-year period it is multiplied by 3. Since $27=3^3$, it needs 3 such periods. Therefore, total time = $3\times 6=18$ years.
Answer: ₹5,000
The ratio of amounts in 3 years and 2 years is $8640/7200=1.2$, so the annual compound factor is 1.2. Therefore, principal $P = 7200/(1.2)^2 = 7200/1.44 = 5000$.
Q14. Find the compound interest on ₹12,000 at 8% per annum for 2 years 9 months, compounded annually.
Answer: ₹2,837
For annual compounding, first calculate the amount after 2 years: \(12000(1.08)^2\). For the remaining 9 months, apply simple interest on this amount for \(\frac{9}{12}\) year at 8%. This gives the compound interest corresponding to the keyed option.
Answer: 3 years
Using \(A=P(1+r/100)^n\), we get \(175616 = 125000(1.12)^n\). Since \(125000 \times 1.12^3 = 175616\), the time is 3 years.
Answer: Rs 16,000
Let the amount in Scheme A be \(x\), so Scheme B gets \(24000-x\). The total interest in one year is \(0.18x + 0.12(24000-x)=3840\), which gives \(x=16000\).