Exams › SSC CGL (Prelims) › General

A special operator is defined so that \(4 \oplus 3 = 19\) and \(5 \oplus 2 = 17\). Using the same rule, what is the value of \(6 \oplus 4\)?

1. 24
2. 28
3. 34
4. 32

Correct answer: 34

Solution

The pattern fits \(a \oplus b = ab + a + b\). For \(4 \oplus 3\), \(4\cdot3+4+3=19\), and for \(5 \oplus 2\), \(5\cdot2+5+2=17\). Therefore, \(6 \oplus 4 = 6\cdot4+6+4 = 34\).

Related SSC CGL (Prelims) General questions

• If \(a \% b = a^2 - b^2\) and \(a \% b = 63\), find \(a\) and \(b\).
• How many letters will remain unchanged if the word EDUCATION is arranged in alphabetical order?
• Select the letter cluster that will replace (?): B, F, J, N, R, V, Z, ?
• Pointing to a boy, a woman said, “He is the son of my father’s only daughter.” How is the boy related to the woman?
• If $4 \oplus 3 = 19$ and $5 \oplus 2 = 17$, then $6 \oplus 4 = ?$
• If $3x + 7 = 28$, find $x$.

⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →