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An 80-litre mixture contains milk and water in the ratio 7:1. Some quantity of this mixture is removed and replaced with pure milk. If the final ratio of milk to water becomes 15:1, how many litres of the mixture were replaced?
- 40 litres
- 18 litres
- 32 litres
- 46 litres
Correct answer: 40 litres
Solution
Initially, milk = 70 L and water = 10 L. If \(x\) litres of mixture are removed, water left = \(10 - \frac{x}{8}\) and milk left = \(70 - \frac{7x}{8}\); then \(x\) litres of pure milk are added. The final ratio becomes 15:1, which gives \(x=40\).
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