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A contractor hires 10 workers who can complete a task in 16 days. After 4 days, he fires 2 workers. How many more days will the remaining workers take to complete the task?

1. 13 days
2. 14 days
3. 15 days
4. 16 days

Correct answer: 15 days

Solution

Total work = \(10\times16=160\) worker-days. In 4 days, 10 workers do \(10\times4=40\) worker-days, leaving \(120\) worker-days. After 2 workers are fired, 8 workers remain, so time needed = \(120/8=15\) days.

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