A ball is thrown vertically upward with an initial velocity of 10 m/s. Ignoring air resistance, what is the maximum height it will reach? (Assume $g = 9.8\, ext{m/s}^2$)

Question

A ball is thrown vertically upward with an initial velocity of 10 m/s. Ignoring air resistance, what is the maximum height it will reach? (Assume $g = 9.8\,	ext{m/s}^2$)

Accepted Answer

5.10 m. At the maximum height, the final velocity becomes zero. Using $0 = u^2 - 2gh$, we get $h = \frac{u^2}{2g} = \frac{100}{19.6} \approx 5.10$ m.

A ball is thrown vertically upward with an initial velocity of 10 m/s. Ignoring air resistance, what is the maximum height it will reach? (Assume $g = 9.8\,\text{m/s}^2$)

Solution

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