Exams › SSC CGL (Prelims) › General

Find the point where the line y = 3x - 12 crosses the x-axis.

1. (0, -12)
2. (-4, 0)
3. (0, 4)
4. (4, 0)

Correct answer: (4, 0)

Solution

A line crosses the x-axis where y = 0. Putting y = 0 in y = 3x - 12 gives 0 = 3x - 12, so x = 4. Hence the point is (4, 0).

Related SSC CGL (Prelims) General questions

• What is the equation of a line passing through \((0,4)\) with slope \(-2\)?
• What is the slope of the line perpendicular to $y = 5x - 8$?
• Which line has slope \(-2\) and passes through \((3,5)\)?
• A line \(L\) is the perpendicular bisector of the line segment joining points \(P(4,6)\) and \(Q(10,2)\). What is the y-intercept of line \(L\)?
• Find the slope of the line $4x - 5y = 10$.
• Find the equation of the perpendicular bisector of the line segment joining the points $(1,5)$ and $(5,9)$.

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