Exams › SSC CGL (Prelims) › General

Simplify: \(\sqrt{20} + \sqrt{125}\)

1. 6 \(\sqrt{5}\)
2. 7 \(\sqrt{5}\)
3. 8 \(\sqrt{5}\)
4. 9 \(\sqrt{5}\)

Correct answer: 7 \(\sqrt{5}\)

Solution

\(\sqrt{20} = \sqrt{4\cdot 5} = 2\sqrt{5}\) and \(\sqrt{125} = \sqrt{25\cdot 5} = 5\sqrt{5}\). Adding them gives \(2\sqrt{5}+5\sqrt{5}=7\sqrt{5}\).

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