Exams › SSC CGL (Prelims) › General
Correct answer: 0.008
We have $0.13^3 = (13\times10^{-2})^3 = 13^3\times10^{-6}$ and $0.013^3 = (13\times10^{-3})^3 = 13^3\times10^{-9}$. Similarly, the denominator becomes $53^3\times10^{-6} + 53^3\times10^{-9}$. After factoring, the ratio simplifies to $\left(\frac{13}{53}\right)^3 \approx 0.008$.