Exams › SSC CGL (Prelims) › General
Correct answer: (2, 4)
For a triangle with vertices A(x1,y1), B(x2,y2), C(x3,y3), the centroid is \(\left(\frac{x1+x2+x3}{3},\frac{y1+y2+y3}{3}\right)\). Using G(2,4), A(5,2), and B(-1,6), solve for C. The coordinates come out to (2,4).