Exams › SSC CGL (Prelims) › General

The graph of the equation \(2x + 5y = 10\) passes through which point?

1. (5, 0)
2. (0, 2)
3. (-5, 4)
4. All of the above

Correct answer: All of the above

Solution

Substituting \((5,0)\) gives \(2(5)+5(0)=10\), and substituting \((0,2)\) gives \(2(0)+5(2)=10\). But \((-5,4)\) gives \(-10+20=10\), so all listed points satisfy the equation.

Related SSC CGL (Prelims) General questions

• What is the equation of a line passing through \((0,4)\) with slope \(-2\)?
• What is the slope of the line perpendicular to $y = 5x - 8$?
• Which line has slope \(-2\) and passes through \((3,5)\)?
• A line \(L\) is the perpendicular bisector of the line segment joining points \(P(4,6)\) and \(Q(10,2)\). What is the y-intercept of line \(L\)?
• Find the slope of the line $4x - 5y = 10$.
• Find the equation of the perpendicular bisector of the line segment joining the points $(1,5)$ and $(5,9)$.

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