Exams › SSC CGL (Prelims) › General

$18^3 + 14^3 - 32^3 + 24192$ is equal to:

1. 0
2. 1
3. -24192
4. 48384

Correct answer: 0

Solution

Using the identity $a^3+b^3-(a+b)^3=-3ab(a+b)$, with $a=18$ and $b=14$, we get $18^3+14^3-32^3=-3\cdot18\cdot14\cdot32=-24192$. Adding $24192$ gives $0$.

Related SSC CGL (Prelims) General questions

• What is the value of \(5 + 55 + 555 + 5555 + 55555\)?
• Simplify: \((214 + 3.8) - 215\)
• If $x = \sqrt{6} - \sqrt{2}$ and $y = \sqrt{5} - \sqrt{3}$, then which of the following is true?
• Evaluate: $\left(15 \div 13\right) \div \left(\frac{1}{10} + 1 - \frac{8}{10}\right)$
• Which of the following equals 20?
• A runner has to cover a distance of 100 km. After running for 5 hours 20 minutes, he finds that he has completed \(\tfrac{2}{3}\) of the total distance. What is his speed in km/h?

⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →