Exams › SSC CGL (Prelims) › General
In \(\triangle PQR\), medians \(PL\), \(QM\), and \(RN\) intersect at centroid \(G\). If the area of \(\triangle PQR\) is 72 cm², what is the area of \(\triangle GQR\)?
- 12 cm²
- 18 cm²
- 24 cm²
- 36 cm²
Correct answer: 24 cm²
Solution
The centroid divides the triangle into six smaller triangles of equal area. Therefore, triangle \(GQR\) occupies one-third of the area of \(\triangle PQR\), which is 72/3 = 24 cm².
Related SSC CGL (Prelims) General questions
⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →