Exams › SSC CGL (Prelims) › General
Correct answer: 13 cm
The radius to the point of tangency is perpendicular to the tangent, so the center, tangency point, and external point form a right triangle. The radius is 5 cm and the tangent length is 12 cm, so the distance from the center to M is \(\sqrt{5^2+12^2}=13\) cm.