Exams › SSC CGL (Prelims) › General

What is the value of \((0.2^3+0.3^3)\div(0.6^3+0.9^3)\)?

1. \(\frac{1}{3}\)
2. \(\frac{1}{9}\)
3. \(\frac{1}{27}\)
4. \(\frac{1}{8}\)

Correct answer: \(\frac{1}{27}\)

Solution

The denominator terms are each 3 times the corresponding numerator terms, so each cube becomes 27 times larger. Hence the whole ratio is \(1/27\).

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