Exams › SSC CGL (Prelims) › General

Find the midpoint of the segment joining \((4,-2)\) and \((10,6)\).

1. (7, 4)
2. (6, 2)
3. (7, 2)
4. (5, 3)

Correct answer: (7, 2)

Solution

The midpoint of two points is found by averaging their coordinates. Here, \(x=\frac{4+10}{2}=7\) and \(y=\frac{-2+6}{2}=2\). So the midpoint is \((7,2)\).

Related SSC CGL (Prelims) General questions

• What is the equation of a line passing through \((0,4)\) with slope \(-2\)?
• What is the slope of the line perpendicular to $y = 5x - 8$?
• Which line has slope \(-2\) and passes through \((3,5)\)?
• A line \(L\) is the perpendicular bisector of the line segment joining points \(P(4,6)\) and \(Q(10,2)\). What is the y-intercept of line \(L\)?
• Find the slope of the line $4x - 5y = 10$.
• Find the equation of the perpendicular bisector of the line segment joining the points $(1,5)$ and $(5,9)$.

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