Exams › SSC CGL (Prelims) › General
If 9#2 = 83 and 8#3 = 67, then 7#4 = ?
- 51
- 58
- 53
- 47
Correct answer: 53
Solution
A suitable rule is \(a#b = (a \times b) - (a + b)\). For 9#2, \(18 - 11 = 7\), which does not match, so try another pattern: \(a#b = a^2 - b\) gives 79, not 83. The matching rule is \(a#b = a^2 - (b+? )\) not direct; instead, the given examples fit \(a#b = (a^2 - b^2) + 2\): for 9#2, 81 - 4 + 6 = 83 and for 8#3, 64 - 9 + 12 = 67. Applying the same pattern to 7#4 gives 49 - 16 + 20 = 53.
Related SSC CGL (Prelims) General questions
- What comes in place of (?) in the series: 2, 6, 18, 54, ?
- What comes next? 8, 20, 44, 92, ?
- One number does not fit into the given factorial series. Identify it: 3, 6, 24, 120, 720, 800.
- What should come at the place of the question mark (?) in the following series? 2, 3, 8, 9, 26, 27, ?
- Choose the odd one out:
- Complete the pattern: 120, 96, 76.8, 61.44, ?
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