Exams › SSC CGL (Prelims) › General
Correct answer: 12 cm
If two circles touch externally, the distance between their centers is 4 + 9 = 13 cm. The length of the direct common tangent is \(\sqrt{d^2-(r_1-r_2)^2}\) = \(\sqrt{13^2-5^2}\) = \(\sqrt{144}=12\) cm.