Exams › SSC CGL (Prelims) › General
Correct answer: 10 cm
The perpendicular from the center to the chord bisects it, so half the chord is 8 cm. With distance from center 6 cm, the radius is the hypotenuse of a right triangle: \(r^2 = 8^2 + 6^2\). Thus \(r = \sqrt{64+36} = 10\) cm.